Subject: 36-303 Comprehensive Compilation From: "Christopher Peter Makris" Date: Tue, 15 Feb 2011 22:32:42 -0500 To: bj20@andrew.cmu.edu Dear Professor Junker, Hopefully this email includes/summarizes all the recent information from the past 24 hours between the two of us that I was supposed to send you! If I've left anything out, please let me know. ------------------------------ Assignments: -Attached is the I4 "Population, Frame, & Nonresponse Plan" that we were supposed to turn in for today's class. I had brought a hard copy to class today since I am the "final editor" for everything our group submits, but didn't realize we were supposed to just email this one. My apologizes -In a previous email (sent this morning, not attached here), I had sent our "Team Working Agreement," which we also submitted this afternoon signed in hard-copy form -Since we thought it was due today, our team had also completed a draft of the IRB form (attached here). I think you mentioned in class today that you would be willing to check a draft of this before we submit the final copy. If you wouldn't mind, that would be greatly appreciated since there were a few questions we weren't sure if we were answering correctly. Also attached are our team's Human Subjects Research proofs (in a .zip folder). Some of us took these quizzes from previous classes. These are what we plan on attaching to our group's IRB form to complete it ------------------------------ ------------------------------ Grading: On Homework #3, many students lost points on questions #2a, #2b, and #3a. Summaries of what we (or at least I) wrote for these questions are listed below: -Question #2a: Most students lost 4 points for writing the following proof: E[aX + bY + c] = = E[aX] + E[bY] + E[c] (by Linearity Of Expectation) = = aE[X] + bE[Y] + c (Q.e.d) -Question #2b: Most students lost 4 points for writing the following proof: Var[aX + bY + c] = = Var[aX + bY] = = Var[aX] + Var[bY] + 2Cov[aX, bY] = = a^2Var[X] + b^2Var[Y] + 2Cov[aX, bY] = = a^2Var[X] + b^2Var[Y] + 2(E[abXY] - E[aX]E[bY]) = = a^2Var[X] + b^2Var[Y] + 2(abE[XY] - abE[X]E[Y]) = = a^2Var[X] + b^2Var[Y] + 2ab(E[XY] - E[X]E[Y]) = = a^2Var[X] + b^2Var[Y] + 2abCov[X,Y] (Q.e.d) -Question #3a: Most students lost 3 points for writing that E[lambda-hat] = lambda somewhere within their proof ------------------------------ ------------------------------ Spring Break: Since I will be driving back home, I will be able to stay in town as long as I want to. I probably will leave sometime on Saturday evening or Sunday morning, but this is not set in stone. Therefore, I would have no conflicts and would absolutely love introducing someone to the Carnegie Mellon campus! Just let me know any necessary details when/if this comes to fruition. ------------------------------ Thanks so much!!! :) Sincerely, -Christopher Peter Makris Population, Frame, & Nonresponse Plan.docx Content-Type: application/vnd.openxmlformats-officedocument.wordprocessingml.document Content-Encoding: base64 IRB Application.doc IRB Application.doc Content-Type: application/msword Content-Encoding: base64 Human Subjects Research Proof.zip Human Subjects Research Proof.zip Content-Type: application/x-zip-compressed Content-Encoding: base64